Minimum Insertion Steps to Make a String Palindrome
Problem Statement
You are given a string s. In one step you may insert any letter at any position in s, including the start and the end. Return the fewest insertions that turn s into a palindrome. A palindrome reads the same forwards and backwards.
A string s of lowercase letters.
The smallest number of insertions that makes s a palindrome.
The string is already a palindrome, so nothing needs to be inserted.
One result is mbdadbm. It inserts a d after the b and a b before the last m.
One result is leetcodocteel, which adds five letters to the original eight.
- • 1 ≤ s.length ≤ 500
- • s consists of lowercase English letters.
Pattern Recognition Clues
Recognising these key signals in the problem description immediately identifies the pattern:
Approach Complexity Ladder
Ends match: solve the inside. Ends differ: insert one end, solve the rest, keep the cheaper choice
dp[i][j] is the fewest insertions for s[i..j]; fill the table from the last row up
Compute the longest palindromic subsequence with one row, and return n minus it
For s[i..j]: if s[i] = s[j], the ends pair up for free, so the cost is the cost of the inside. If they differ, one insertion settles one end. Insert a copy of s[i] on the right, which leaves s[i+1..j]. Or insert a copy of s[j] on the left, which leaves s[i..j−1]. Take the cheaper of the two, plus 1.
Recognition rule for this sub-pattern:
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